Passing variable no of arguments in a perl script


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Thread: Passing variable no of arguments in a perl script


SmallWonder
Hello Friends

I am New to Perl Programming.

I am in a Problem.

I have to write a Perl Script which will take variable no of arguments
and will perform accordingly. This can take 1 or 2 or 3.. no of arguments.
Suppose:

Myscript.pl -p
Myscript.pl -p -v
Myscript.pl -p -l
Myscript.pl -p -l -v filename

in all these cases it will perform accordingly.

I have no idea how to handle it.

Please Help me.

Thanks in Advance

Manish